x^y=y^x , find dy/dx | first order derivative
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`(cosx)^(y)=(siny)^(x)`
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If `cos y = x cos (a + y)` , with `cos a!=+-1` , prove that `(dy)/(dx)=(cos^2(a+y)/(sina))` ....
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#ifcosy=xcos #thenprovethatdy/dx=cos²/sina.siny=xsinfinddy/dxdy/dx=sina/
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